Blue Andred Marbles Bag Problem

This is called probability without replacement or dependent probability.

Blue andred marbles bag problem.

A if you repeated this experiment a very large number of times on average how many draws would you make before a blue marble was drawn. You draw a marble at random without replacement until the first blue marble is drawn. 2 making a table 6 rp 3a 6 ee 7 we are given that for every three blue marbles in the bag there are two red marbles. For example a marble may be taken from a bag with 20 marbles and then a second marble is taken without replacing the first marble.

No packages or subscriptions pay only for the time you need. Answer by fombitz 32378 show source. Initially blue marbles red marbles x then john. With our new ratio of 3 4 for blue marbles to red marbles this means that 4 out of every 7 marbles in the bag are red.

John took out 5 blue marbles and then there were twice as many red marbles as blue marbles in the bag. A bag has 3 blue marbles and 4 red marbles. Most questions answered within 4 hours. Get a free answer to a quick problem.

So frac 4 7 of the marbles are now red. So they say the probability i ll just say p for probability. And so this is sometimes the event in question right over here is picking the yellow marble. What is the chance that the first draw is a red marble.

Let x red marbles. Find the probability of pulling a yellow marble from a bag with 3 yellow 2 red 2 green and 1 blue i m assuming marbles. The sample space for the second event is then 19 marbles instead of 20 marbles. A bag has 16 blue 20 red and 24 green marbles.

What fraction of the marbles in the bag are blue. Find an online tutor now choose an expert and meet online. You reach into the bag and draw a marble and then draw another marble without replacing the first one. Initially there were the same number of blue marbles and red marbles in a bag.

If the first marble drawn was a red marble what is the chance that the second draw is a blue marble. The number of blue marbles is 1 less than 3 times the number of red marbles. Let x the number of draws. How many red marbles are there in the bag.

A bag contains blue marbles and red marbles 71 in total. So simple multiplication will give the desired probability. Since the first marble is replaced before the second marble is drawn the colour of the second marble is independent of the colour of the first marble.